ESP8266 Interrupt problem
Posted: Fri Jul 13, 2018 2:31 pmHi,
Im trying to run an interrupt on Wemos D1 mini D4 pin.
Do I need any resistor/capacitor when using
(or just switch between gnd and D4?)
Instead 1 interrupt i get a series (I get an interrupt on pressing and releasing switch despite FALLING option).
The idea is to get an interrupt on pressing the switch.
Im trying to run an interrupt on Wemos D1 mini D4 pin.
Do I need any resistor/capacitor when using
Code: Select all
?pinMode(buttonPin, INPUT_PULLUP);(or just switch between gnd and D4?)
Instead 1 interrupt i get a series (I get an interrupt on pressing and releasing switch despite FALLING option).
The idea is to get an interrupt on pressing the switch.
Code: Select all
#include <ESP8266WiFi.h>
#include <PubSubClient.h>
const char* ssid = "xxx";
const char* password = "xxx";
const char* mqtt_server = "192.168.1.200";
const char* mqttUser = "mosquitto";
const char* mqttPassword = "mosquitto1";
const int mqttPort = 1883;
const int buttonPin = 2;
volatile byte buttonState = LOW;
unsigned long aktualnyCzas = 0;
WiFiClient espClient;
PubSubClient client(espClient);
void setup() {
//pinMode(buttonPin, INPUT);
pinMode(buttonPin, INPUT_PULLUP);
Serial.begin(115200);
Serial.println("----");
WiFi.begin( ssid, password );
while (WiFi.status() != WL_CONNECTED)
{
delay(1);
}
client.setServer(mqtt_server, mqttPort);
while (!client.connected())
{
if (client.connect("Przycisk2", mqttUser, mqttPassword ))
{
}
else
{
}
}
attachInterrupt(digitalPinToInterrupt(buttonPin), sendmqtt, FALLING);
delay(1000);
}
void sendmqtt() {
buttonState = 1;
}
void loop() {
client.loop();
if (buttonState == 1)
{
detachInterrupt(buttonPin);
buttonState=0;
client.publish("ha/switch1", "ON");
aktualnyCzas = millis();
Serial.println(aktualnyCzas);
delay(1000);
attachInterrupt(digitalPinToInterrupt(buttonPin), sendmqtt, FALLING);
}
}