ESP8266 Community Forum

Note that I'm an extremely new to C++. I'm wondering how this bit of code works:



It seems to be like calling connect here should be accessing a method on a NULL object, but it's not. Does this method somehow act as a constructor too?

Howdy Ben,
You didn't mention what programming languages you are familiar with.

In C++ if X is a class type then:

X a;

creates an instance of X and a becomes a reference to it. In Java, a similar thing such as:

X a;

would be treated as a being a variable of type X but not an instance. One would code:

X a = new X();

in C++ the above is:

X a;

Neil

Hi,

A little explanation here:


This creates an instance of WifiClient and name it client. The constructor of WifiClient runs here, e.g it setup basic parameter for the wifi connection.


We call a method called 'connect' of the instance 'client'.
client.connect(host, httpPort) will return a value, if it is ZERO - indicate that it is failed by the one who programmed it, code in the block will run.

Bad code practice though, IMO

Dat

Thanks for the replies guys, I didn't realize C++ had implicit initialization like that (or Java either for that matter--EDIT: never mind, just reread your post and realized you used Java as a counter example).

I code Objective-C all day so I'm used to explicitly initializing everything. Thanks for the help, I wasn't sure what to search for so figured I'd just ask here.