- Sun Aug 20, 2017 3:31 pm
#69338
rudy wrote:trackerj I have used those boards. They are adequate. I'm sure you would rather sell your boards but there are acceptable less expensive alternatives.
Also, would you go with more than 3Amps load with that thin traces? I don't think so, you are way too experienced for doing that.
For higher currents I would remove the shunt resistor and use an external shunt. The current shunt could be left in place, it would just have to be included with the external shunt's resistance.
As far as my experience. I have been working designing commercial products for over 30 years.
I am really sorry and must apologize if somehow I was misunderstood. It was no sarcastic remark in the sentence : " I don't think so, you are way too experienced for doing that." Literally, I know you have enough experience to know that. And you probably also know also that I have also enough.
I am not trying to sell anything here. Everybody is free to buy/use whatever they want. I am just trying to help people less experienced to learn something in the right way. If you used such a beautiful board, how thick is the load trace? And how big was your load target? under or over 3Amps? What was the quality of the shut resistor? I don't expect a high quality, low TCO one for such a price.
Only with the Shenzen market "magic" you can have a brand new,genuine 1.5$ INA219 + a 5$ good quality shunt resistor and a well designed PCB for a complete device that will cost only 1.5$. yeah. magic. You know is no "magic" there. Just low quality, grey market or defective components.
And to know exactly what's the board we are talking about, it's about this one or similar?
http://www.ebay.com/itm/INA219-GY-219-B ... SwEzxYZxykIf you use an external shunt resistor and also load circuit then the fancy 2$ Ebay board has just become somehow just a expensive smd adapter for the INA219 IC, isn't it correct? And by the way, don't you loose then also the the short lenght, balanced, kelvin current sensing traces connection to INA219 that will help you to have the best accuracy over the entire measurement domain?
Also, can you please elaborate a bit more the idea from here: "The current shunt could be left in place, it would just have to be included with the external shunt's resistance."
Let's help people to learn something about.
Happy breadboarding,
TJ.