ESP8266 Community Forum

- Tue Jun 16, 2015 12:31 am #20557 Thanks . you probably mean drive it low to turn it off.

#define DIGITAL_PIN 1
#define LED_ON digitalWrite(DIGITAL_PIN, 0)
#define LED_OFF digitalWrite(DIGITAL_PIN, 1)
pinMode(DIGITAL_PIN, OUTPUT);

Would pinMode(1, INPUT); do the same?

Get you modules here:

https://www.banggood.com/custlink/KvGGhGF4wG

- Tue Jun 16, 2015 4:26 am #20580 Hi,

> Thanks . you probably mean drive it low to turn it off.
>
no, turn LED on by setting pin1 to 0, turn LED off by setting pin1 to 1.

> Would pinMode(1, INPUT); do the same?
>
With OUTPUT you get a bright LED, with INPUT a very dim LED when turned on.

Hermann.

- Tue Jun 16, 2015 4:38 am #20581 So the LED is run via a resistor to source voltage? so making pin high turns off and pin low turns on . Its sinking through the chip

With OUTPUT you get a bright LED, with INPUT a very dim LED when turned on.

That will come in handy for power saving
OK thanks

Get you modules here:

https://www.banggood.com/custlink/KvGGhGF4wG

- Wed Jun 17, 2015 2:27 am #20663 From here ("… #LED has three states (off, dim, on) …"):
https://twitter.com/HermannSW/status/579690784871571458



Hermann.